anonymous
  • anonymous
straightforward question: How do I find the inverse laplace of (1/(s^2+1)^2)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
If it helps, the answer is 1/2*sin(t)-1/2*t*cos(t), but how do I get that answer?
anonymous
  • anonymous
Use F(s)=2bs/(s^2+b^2)^2. Everythign fits that form except for the 2, so you multiple the top and bottom by 2. Factor out the bottom 2 to get the 1/2, and then plug in the f(t) from table
anonymous
  • anonymous
? There is no s in the numerator

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anonymous
  • anonymous
oops sorry i copied wrong one down from table, i meant 2b^3/(s^2+b^2)^2
anonymous
  • anonymous
1. Which table are you looking at? Mine only contains very basic and common transforms. and 2. Is there a way to do it using more simple table references? (e.g. using only knowledge of basic Laplace properties and knowledge of Laplace transforms of t, sint, and cost, using partial fractions or something similar?)
anonymous
  • anonymous
http://tutorial.math.lamar.edu/Classes/DE/Laplace_Table.aspx it's number 11 on this table, and it showed up on mine from class as well i dont know how to do it any other way, it has no partial fractions sorry

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