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anonymous

  • 5 years ago

how do i find the zeros of the polynomial function, f(x)=2x^3-9x+3? pleassseee help!

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  1. bahrom7893
    • 5 years ago
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    set that equal to 0

  2. bahrom7893
    • 5 years ago
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    2x^3 - 9x + 3 = 0

  3. bahrom7893
    • 5 years ago
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    now try factoring using long division.. lemme see

  4. anonymous
    • 5 years ago
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    okay, so frist what i do is set f(x) to 0? and solve?

  5. bahrom7893
    • 5 years ago
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    yeah

  6. anonymous
    • 5 years ago
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    I think it shoild be 2x^3-9x+2

  7. anonymous
    • 5 years ago
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    Are you sure it's raised to the 3rd power and not the second?

  8. anonymous
    • 5 years ago
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    no dipin, it is +3 not +2 veronometry, yes it is rasied to the 3rd degree

  9. bahrom7893
    • 5 years ago
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    im trying to factor using long division lol..

  10. anonymous
    • 5 years ago
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    what i don't understand is the steps i need to find the 0's?

  11. bahrom7893
    • 5 years ago
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    wait im working on it..

  12. anonymous
    • 5 years ago
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    okay thanks bahrom7893

  13. bahrom7893
    • 5 years ago
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    u can't solve here.. i just tried factoring with wolf..

  14. anonymous
    • 5 years ago
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    what i need help with more than anything is understanding what i need to do in order. i suppose like a step by step list to understand how to find the zeros of a polynomial function

  15. anonymous
    • 5 years ago
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    what is wolf?

  16. bahrom7893
    • 5 years ago
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    wolframalpha.com

  17. bahrom7893
    • 5 years ago
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    To do step by step, first set the polynomial equal to 0, then try factoring or use the quadratics..

  18. anonymous
    • 5 years ago
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    The zeros of any function is the same as finding the x-intercept. And, since ANY x-intercept has a y value of 0, you set he entire function equal to zero in order to solve for x. That way, when you solve for x, you get ordered pair(s) of (x,0) etc (depending on the degree of your function. There are some exceptions to that rule, but for the most part it's the same. Does that help?

  19. anonymous
    • 5 years ago
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    I undertstand now that i frist need to set the equation equal to 0. other than that do i just try to balance out the equation?

  20. anonymous
    • 5 years ago
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    or do all the x's in the equation turn to 0\

  21. bahrom7893
    • 5 years ago
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    no u just need to find xs that make the y or f(x) go to 0

  22. anonymous
    • 5 years ago
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    okay this is where i have gotten \[2x^3-9x+3=0\] i added 3 to both sides \[2x^3-9x=-3\] i divided each side by 2 \[x^3-9x=-1.5\] now what?

  23. bahrom7893
    • 5 years ago
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    see I dunno if there was a 0 instead of -1.5 we could solve it... but even if u add a 1.5 to both sides ull end up with a 1.5 on the right..sorry i can't solve it..

  24. anonymous
    • 5 years ago
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    its okay m just trying to find the 0;s not slove the equations

  25. anonymous
    • 5 years ago
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    Bahrom is right, it's unfactorable. That means you have no zeros. Which means there are no x-intercepts. The graph is probably floating above or below the x-axis.

  26. anonymous
    • 5 years ago
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    Btw, you can't divide both sides by 2. You can only do that if you factor out a 2 from both of the terms.

  27. anonymous
    • 5 years ago
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    okay i believe you because i have no idea what the hell i am doing lol

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