anonymous
  • anonymous
how do i find the zeros of the polynomial function, f(x)=2x^3-9x+3? pleassseee help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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bahrom7893
  • bahrom7893
set that equal to 0
bahrom7893
  • bahrom7893
2x^3 - 9x + 3 = 0
bahrom7893
  • bahrom7893
now try factoring using long division.. lemme see

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anonymous
  • anonymous
okay, so frist what i do is set f(x) to 0? and solve?
bahrom7893
  • bahrom7893
yeah
anonymous
  • anonymous
I think it shoild be 2x^3-9x+2
anonymous
  • anonymous
Are you sure it's raised to the 3rd power and not the second?
anonymous
  • anonymous
no dipin, it is +3 not +2 veronometry, yes it is rasied to the 3rd degree
bahrom7893
  • bahrom7893
im trying to factor using long division lol..
anonymous
  • anonymous
what i don't understand is the steps i need to find the 0's?
bahrom7893
  • bahrom7893
wait im working on it..
anonymous
  • anonymous
okay thanks bahrom7893
bahrom7893
  • bahrom7893
u can't solve here.. i just tried factoring with wolf..
anonymous
  • anonymous
what i need help with more than anything is understanding what i need to do in order. i suppose like a step by step list to understand how to find the zeros of a polynomial function
anonymous
  • anonymous
what is wolf?
bahrom7893
  • bahrom7893
wolframalpha.com
bahrom7893
  • bahrom7893
To do step by step, first set the polynomial equal to 0, then try factoring or use the quadratics..
anonymous
  • anonymous
The zeros of any function is the same as finding the x-intercept. And, since ANY x-intercept has a y value of 0, you set he entire function equal to zero in order to solve for x. That way, when you solve for x, you get ordered pair(s) of (x,0) etc (depending on the degree of your function. There are some exceptions to that rule, but for the most part it's the same. Does that help?
anonymous
  • anonymous
I undertstand now that i frist need to set the equation equal to 0. other than that do i just try to balance out the equation?
anonymous
  • anonymous
or do all the x's in the equation turn to 0\
bahrom7893
  • bahrom7893
no u just need to find xs that make the y or f(x) go to 0
anonymous
  • anonymous
okay this is where i have gotten \[2x^3-9x+3=0\] i added 3 to both sides \[2x^3-9x=-3\] i divided each side by 2 \[x^3-9x=-1.5\] now what?
bahrom7893
  • bahrom7893
see I dunno if there was a 0 instead of -1.5 we could solve it... but even if u add a 1.5 to both sides ull end up with a 1.5 on the right..sorry i can't solve it..
anonymous
  • anonymous
its okay m just trying to find the 0;s not slove the equations
anonymous
  • anonymous
Bahrom is right, it's unfactorable. That means you have no zeros. Which means there are no x-intercepts. The graph is probably floating above or below the x-axis.
anonymous
  • anonymous
Btw, you can't divide both sides by 2. You can only do that if you factor out a 2 from both of the terms.
anonymous
  • anonymous
okay i believe you because i have no idea what the hell i am doing lol

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