how do i find the zeros of the polynomial function, f(x)=2x^3-9x+3? pleassseee help!

- anonymous

how do i find the zeros of the polynomial function, f(x)=2x^3-9x+3? pleassseee help!

- katieb

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- bahrom7893

set that equal to 0

- bahrom7893

2x^3 - 9x + 3 = 0

- bahrom7893

now try factoring using long division.. lemme see

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## More answers

- anonymous

okay, so frist what i do is set f(x) to 0? and solve?

- bahrom7893

yeah

- anonymous

I think it shoild be 2x^3-9x+2

- anonymous

Are you sure it's raised to the 3rd power and not the second?

- anonymous

no dipin, it is +3 not +2
veronometry, yes it is rasied to the 3rd degree

- bahrom7893

im trying to factor using long division lol..

- anonymous

what i don't understand is the steps i need to find the 0's?

- bahrom7893

wait im working on it..

- anonymous

okay thanks bahrom7893

- bahrom7893

u can't solve here.. i just tried factoring with wolf..

- anonymous

what i need help with more than anything is understanding what i need to do in order. i suppose like a step by step list to understand how to find the zeros of a polynomial function

- anonymous

what is wolf?

- bahrom7893

wolframalpha.com

- bahrom7893

To do step by step, first set the polynomial equal to 0, then try factoring or use the quadratics..

- anonymous

The zeros of any function is the same as finding the x-intercept. And, since ANY x-intercept has a y value of 0, you set he entire function equal to zero in order to solve for x. That way, when you solve for x, you get ordered pair(s) of (x,0) etc (depending on the degree of your function. There are some exceptions to that rule, but for the most part it's the same. Does that help?

- anonymous

I undertstand now that i frist need to set the equation equal to 0.
other than that do i just try to balance out the equation?

- anonymous

or do all the x's in the equation turn to 0\

- bahrom7893

no u just need to find xs that make the y or f(x) go to 0

- anonymous

okay this is where i have gotten
\[2x^3-9x+3=0\]
i added 3 to both sides
\[2x^3-9x=-3\]
i divided each side by 2
\[x^3-9x=-1.5\]
now what?

- bahrom7893

see I dunno if there was a 0 instead of -1.5 we could solve it... but even if u add a 1.5 to both sides ull end up with a 1.5 on the right..sorry i can't solve it..

- anonymous

its okay
m just trying to find the 0;s not slove the equations

- anonymous

Bahrom is right, it's unfactorable. That means you have no zeros. Which means there are no x-intercepts. The graph is probably floating above or below the x-axis.

- anonymous

Btw, you can't divide both sides by 2. You can only do that if you factor out a 2 from both of the terms.

- anonymous

okay i believe you because i have no idea what the hell i am doing lol

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