A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

solve using common base 3^(x + 3) - 3^x = 78

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[3^{x+3}-3^{x}=78\]

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Demmit! Hold on. I clicked prematurely.

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    From the first post, and using the properties of exponents, we can rewrite the first term as: \[3^{x}3^{3}-3^{x}=78\] Then, you can see that you can factor out a 3^x to get: \[3^{x}(3^{3}-1) = 78\] Simplify what's inside the parenthesis to get: \[3^{x}(27-1)=78\]\[3^{x}(26)=78\]Divide both sides by 26 to get: \[3^{x}=3\] Now, what value of x do you need to make this statement true? 1. Why because \[3^{1}=3\] Therefore, x = 1. The end.

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.