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anonymous
 5 years ago
find the volume of the solid using shell method, region of y=sqrt2, x=y^2 , x=0. about the xaxis
anonymous
 5 years ago
find the volume of the solid using shell method, region of y=sqrt2, x=y^2 , x=0. about the xaxis

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok which function is on top?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y=sqrt2, bounded on left by y axis and below by x=y^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just confirming it is y=\[y=\sqrt(2)\] x= x^2 right functions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so x=y^2 is a side way parabola facing in the positive x direction(right) y=sqrt(2) is just a horizonal striaght line We need to find intersection of of lines

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The intersection point will have y=sqrt(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is x intersection is 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the region we are rotating has these points(0,0) origin (0,sqrt(2)top left corner, (2,sqrt(2) intersection

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so far good, i have a drawing set up

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So we are going to use shell method which is just add up bunch off cylinder

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Volume of cylinder is pi*radius^2*h

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if you look your drawing(may be draw horizonal rectangle) you will see that the y value of function represent radius

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the function x=y^2 represent h

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea from the integral of 0 to sqrt2 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2\pi\int\limits(y*y^2 dy(\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you got the limit of the integration right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so just integrate that? with the height as y^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oooh thank you, i kept thinking of subtracting sqrt2 from the height wasn't really paying attention that this was respect to y. Thank you for all your help:)
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