## anonymous 5 years ago how do you differentiate f(t)=46+2sin(2t/3)?

1. anonymous

i think you need to use chain rule. the 2 in front of sine is throwing me off a bit i admit. the derivative of 46 is 0. and then with chain rule. $2\sin (2t/3)^1$ do the outside function first, in this case sine. so using power rule, you bring the 1 infront of the 2. and then subtract 1 from the exponent. then the derivative of sin(x) is cos(x). $1*2\cos (2t/3)$ then you multiply by the derivative of the inside (2t/3) $(2t/3)=2t*1/3$ power makes the derivative equal 2 and so $2\cos (2t/3)*2=4\cos (2t/3)$

2. anonymous

thank you!

3. anonymous

4/3 is in front