A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

how do you differentiate f(t)=46+2sin(2t/3)?

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i think you need to use chain rule. the 2 in front of sine is throwing me off a bit i admit. the derivative of 46 is 0. and then with chain rule. \[2\sin (2t/3)^1 \] do the outside function first, in this case sine. so using power rule, you bring the 1 infront of the 2. and then subtract 1 from the exponent. then the derivative of sin(x) is cos(x). \[1*2\cos (2t/3)\] then you multiply by the derivative of the inside (2t/3) \[(2t/3)=2t*1/3\] power makes the derivative equal 2 and so \[2\cos (2t/3)*2=4\cos (2t/3)\]

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you!

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    4/3 is in front

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.