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anonymous
 5 years ago
OKSY HOW DO I FIND (X,Y,Z)....
3X+4Y+2Z=24
anonymous
 5 years ago
OKSY HOW DO I FIND (X,Y,Z).... 3X+4Y+2Z=24

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are they both part of the same system?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0WELL WHAT I WAS DOING WAS SOLVE INDIVIDUALY LIKE 3X=24 AND THEN DIVIDING IT TO BOTH SIDES WICH GAVE ME 8 SO X=8 AND THEN I DID THAT TO Y AND Z

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0IM NOT SURE IF THATS CORRECT

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. What is your second equation up there equal to?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I GOT SOMETHING LIKE (3,0,5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0AND FOR MY FRST EQUATION I GOT (8,6,12)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. Those answers aren't correct. If you can tell me what your second equation is equal to then I can help you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OOOH SRRY THE SEC ONE EQUALS 25 I ACCENDENTLY PUT PLUS

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No problem. Solve your first equation for x... x=8(4/3)y(2/3)z...and so... x+3=11(4/3)y(2/3)z... do you follow?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, this gets kind of messy, so it's important that you can get that far, because you also solve it for z & substitute each into your second equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0HEHE OKAY THNX SO MUCH I JUS HAD TO LOOK AT IT A COUPLE OF TIMES TO UNDERSTAND IT THANK YU
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