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anonymous

  • 5 years ago

If z= sqrt[(x^2)y + x(y^2)] and (x, y) changes from (5, 20) to (5.2, 20.4), compare the values of delta z (triangle z) and dz.

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  1. anonymous
    • 5 years ago
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    Okay, I'll take a quick crack at it

  2. anonymous
    • 5 years ago
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    kk

  3. anonymous
    • 5 years ago
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    First off, what is this question for?

  4. anonymous
    • 5 years ago
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    What kind of class?

  5. anonymous
    • 5 years ago
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    calculus 2

  6. anonymous
    • 5 years ago
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    Oohhhh... F... Okay, I'm glad I asked. I'm only in Trig. Coincidentally, my teacher was saying how important trig was for calc 2, but I'm skeptical I can be helpful.

  7. anonymous
    • 5 years ago
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    Considering how dead it is here, I doubt anyone else is on btw...

  8. anonymous
    • 5 years ago
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    I actually came for help on my own homework, but noone responded :P

  9. anonymous
    • 5 years ago
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    thas cool ill get it later

  10. anonymous
    • 5 years ago
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    Hmm... I've my brother, who took calc 2 is up, actually. Lemme Harass er ...ask him.

  11. anonymous
    • 5 years ago
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    What does d in dz mean, btw?

  12. anonymous
    • 5 years ago
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    yo nvm. ill post it again later i think i got it. thnxs

  13. anonymous
    • 5 years ago
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    Alrighty. Take it easy. I'm gonna try to finish my homework now. <_< ^^

  14. anonymous
    • 5 years ago
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    if some1 can solve it that would b good to check my answer thnks

  15. anonymous
    • 5 years ago
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    I'm working on it

  16. anonymous
    • 5 years ago
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    ok thanks

  17. anonymous
    • 5 years ago
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    What did you get for dz?

  18. anonymous
    • 5 years ago
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    i stopped working on it i moved onto the next question

  19. anonymous
    • 5 years ago
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    well you know x=5 y=20 dx=.2 and dy=.4 differentiate z to get dz and then you can plug in the values of x,y,dx,dy resulting in dz

  20. anonymous
    • 5 years ago
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    can u show me the full solution?

  21. anonymous
    • 5 years ago
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    do you know what the correct answer is? just want to check it with mine before I load the full solution

  22. anonymous
    • 5 years ago
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    no i actually dont

  23. anonymous
    • 5 years ago
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    \[dz=[1/2(x^2y+xy^2)^{-1/2}(2xy+y^2)]dx\] \[+ [1/2(x^2y+xy^2)^{-1/2}(x^2+2xy)]\] \[x=5, dx=.2, y=20, dy=.4\] Plug these values in and let me know what you get

  24. anonymous
    • 5 years ago
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    forgot the dy, sorry \[[1/2(x^2y+xy^2)−1/2(x^2+2xy)]dy\]

  25. anonymous
    • 5 years ago
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    gotdamit i messed it up again hold on

  26. anonymous
    • 5 years ago
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    \[+[1/2(x^2y+xy^2)^{−1/2}(x^2+2xy)]dy\]

  27. anonymous
    • 5 years ago
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    Here is the entire equation with any typos, sorry for the confusion \[dz=[1/2(x^2y+xy^2)^{−1/2}(2xy+y^2)]dx\] \[+[1/2(x^2y+xy^2)^{−1/2}(x^2+2xy)]dy\] \[x=5,dx=.2,y=20,dy=.4\]

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