he66666
  • he66666
How do you solve the derivative of 1000(r)^(-1) or 1000(r^(-1))? I know how to solve simple ones but this one confuses me because there's a constant in the front
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
treat the constant as that... a constant if you had f(x)=Ax^2 and A was a constant the derivative would be f'(x)=A2x..... because all a constant does is multiply the function my some factor A
he66666
  • he66666
oh I see. thanks nadeem!
anonymous
  • anonymous
I see how this can be confusing because \[d/dx(c)=0, \] Where c is a constant but \[d/dx=(c*f(x))'=c*f'(x)\]

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anonymous
  • anonymous
I'm sorry made a typo this is what i meant \[d/dx(c)=0,\] and c is a constant \[d/dx(cf(x))=(c∗f(x))'=c*f'(x)\]
anonymous
  • anonymous
I've been up all night study for an exam...lol
he66666
  • he66666
Thanks a bunch. Hope you do well on your exam!

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