anonymous
  • anonymous
Solve for m. √m-7=m +3 a) m = n2 + 6n + 2 b) m = n2 + 6n - 2 c) m = n2 + 6n + 16
Mathematics
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anonymous
  • anonymous
Solve for m. √m-7=m +3 a) m = n2 + 6n + 2 b) m = n2 + 6n - 2 c) m = n2 + 6n + 16
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
sorry the right question is √m-7= n +3
anonymous
  • anonymous
is the 7 under the square root?
anonymous
  • anonymous
c)

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anonymous
  • anonymous
yes the 7 is under the square root
anonymous
  • anonymous
then it is c. you square both sides and then add 7 to each side.

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