• anonymous
If something needs to fall 4 feet to the ground and 3 feet away from its falling point, how fast must the material go if the conveyor belt is a flat plane or 0 degrees. I came up with 5.9 ft per sec but I think it might be a little fast. Can someone show me where I might have gone wrong or am I pretty close?
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • katieb
I got my questions answered at in under 10 minutes. Go to now for free help!
  • sgadi
the formula is \[v=\sqrt{2gh}\] here g=9.8m/s^2=32.152231ft/s^2 and h=3ft so ... velocity = 13.8893 ft/s
  • anonymous
d = Vt - (1/2) a t^2 V in the y direction equals 0 so the Vt term equals 0 d = h = 4 a =32.2 ft/s^2 so \[t = \sqrt{2h/g}\] = .498 s After you find the time that the object is in the air, you can then solve for the velocity in the x direction. It will remain constant because there is no acceleration in the x-direction so d = vt so d in this case would be the x distance which is 3 v = d/t = 3/.498 = 6.02 ft/s You were pretty close
  • anonymous
The velocity term in the first equation I wrote is the initial velocity in the y-direction. That is what is equal to zero. This is because the conveyor is at 0 degrees, so the object comes off moving solely in the x-direction and accelerating solely in the y-direction. I should have been more clear.

Looking for something else?

Not the answer you are looking for? Search for more explanations.