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Hello. Can you draw a simple picture of the problem?
Just so you can visualize it, draw a picture of a flagpole on flat ground.
o ok yes I thought you wanted it on here
Haha, sorry. I just meant on some scratch paper somewhere.
So after you have a flagpole, draw the 32m long rope (and label it 32m) from the top of the flagpole to the ground. The rope should reach 12 meters away from the bottom of the flagpole.
"The rope reaches a place on the ground 12 m from the base of the pole" 12 meters is what I understood.
Regardless. So now you have a picture of a flagpole with rope going diagonally to the ground.
This picture looks an awful lot like a triangle, can we agree?
Great, do you know the parts of your triangles? Right now the rope is the hypotenuse and you should have it labeled 32 meters. From the flagpole to the point where the rope reaches the ground is 12 meters, and you should have it labeled accordingly.
The flagpole coming out of the ground makes a 90 degree angle, that is, the flagpole is perpendicular to the ground. This triangle is a right triangle.
Are we unclear about something?
Oh ok. So we do have a right triangle with the longest side, the hypotenuse being 32 meters. The base of the triangle is 12 meters, from the bottom of the flagpole to the rope.
Do you know about the Pythagorean Theorem?
ok yea I get that and not really sorry
It's fine. The Pythagorean Theorum says that: Triangle: Base ^2 + Height ^2 = Hypotenuse ^2
ok so 32^2 + 12^2 is the answer?
Not quite. So here we have the hypotenuse = 32m and we have the base = 12m. So if we just plug that into our equation: 12^2 + Height^2 (We are missing this variable) = 32^2
So if we evaluate: 144 + H^2 = 1024
Can you isolate and solve for H from here? H=Height of the flagpole.
I am sry I will just get help from my teacher I am just not getting it :(
Oh, it's alright.