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anonymous

  • 5 years ago

Given the function f defined by f(x)=x^2-2x-3, find the equation of the tangent line to the curve at x=3.

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  1. bahrom7893
    • 5 years ago
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    Find first derivative then plug in x = 3 to find the slope..

  2. bahrom7893
    • 5 years ago
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    f' = 2x - 2 f'(3) = 2*3-2 = 4

  3. bahrom7893
    • 5 years ago
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    So slope of tangent line is M = 4

  4. bahrom7893
    • 5 years ago
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    now u need x = 3 and f(3) = 3^2 - 2*3 - 3 = 9 - 6 - 3 = 0 So u have all u need: x = 3; y = 0; M = 4

  5. bahrom7893
    • 5 years ago
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    y - 0 = 4(x-3)

  6. bahrom7893
    • 5 years ago
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    y = 4x - 12

  7. bahrom7893
    • 5 years ago
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    Please click on become a fan if I helped, I really want to get to the next level!! Thanks =)

  8. anonymous
    • 5 years ago
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    Yes. I am understanding this now. These problems are from my old 1972 calculus book.

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