anonymous
  • anonymous
Given the function f defined by f(x)=x^2-2x-3, find the equation of the tangent line to the curve at x=3.
Mathematics
jamiebookeater
  • jamiebookeater
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bahrom7893
  • bahrom7893
Find first derivative then plug in x = 3 to find the slope..
bahrom7893
  • bahrom7893
f' = 2x - 2 f'(3) = 2*3-2 = 4
bahrom7893
  • bahrom7893
So slope of tangent line is M = 4

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bahrom7893
  • bahrom7893
now u need x = 3 and f(3) = 3^2 - 2*3 - 3 = 9 - 6 - 3 = 0 So u have all u need: x = 3; y = 0; M = 4
bahrom7893
  • bahrom7893
y - 0 = 4(x-3)
bahrom7893
  • bahrom7893
y = 4x - 12
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  • bahrom7893
Please click on become a fan if I helped, I really want to get to the next level!! Thanks =)
anonymous
  • anonymous
Yes. I am understanding this now. These problems are from my old 1972 calculus book.

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