## anonymous 5 years ago 2e^x-1=0

1. anonymous

$2e ^{x}-1=0$

2. anonymous

$e^{i\pi} + 1 = 0$ jk $2e^x = 1$ $e^x = 1/2$ $ln(e^x) = ln(1/2)$ $x = ln(1/2)= -.69314718$ Do you understand what I just did?