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anonymous
 5 years ago
What is the graph of this equations such,
1(c=200+50h
2)c=300+25h
c=300+25h=200+50
100=25h
(a)c=200+50h=200+50*4=400
(b)c=300+25*4=400 Just how to find graph equation for those questions thanks
anonymous
 5 years ago
What is the graph of this equations such, 1(c=200+50h 2)c=300+25h c=300+25h=200+50 100=25h (a)c=200+50h=200+50*4=400 (b)c=300+25*4=400 Just how to find graph equation for those questions thanks

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So it looks like you've solved for the intersection point h=4 and c=400. To graph both of these use h for the independent variable (xaxis) and c for the dependent variable (yaxis). The 200 and 300 are the yintercepts (where the lines cross the y axis). The 50 and the 25 are the slopes. To graph the first one 200 is the intercept and 50 is the slope so it passes through the point (1, 250) and (0, 200). Plot those two points and then draw a line through them. Do a similar thing with the other line. This one will pass through points (0, 300) and (1, 325).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you have an equation in the form y = mx + b then the b is where the graph passes through the yaxis (yintercept). The m is the slope. Slope is rise/run or ∆y/∆x. If you have a slope of a positive number (like 50) you go up 50 on the y axis from the yintercept and over 1 on the xaxis.
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