I wonder if anyone can help with a break-even home loand problem Thanks
Stacey Warren - Expert brainly.com
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If you'd post it, that'd be wonderful. :)
1. So it looks like you've solved for the intersection point h=4 and c=400. To graph both of these use h for the independent variable (x-axis) and c for the dependent variable (y-axis). The 200 and 300 are the y-intercepts (where the lines cross the y axis). The 50 and the 25 are the slopes. To graph the first one 200 is the intercept and 50 is the slope so it passes through the point (1, 250) and (0, 200). Plot those two points and then draw a line through them. Do a similar thing with the other line. This one will pass through points (0, 300) and (1, 325).
1. you have an equation in the form y = mx + b then the b is where the graph passes through the y-axis (y-intercept). The m is the slope. Slope is rise/run or ∆y/∆x. If you have a slope of a positive number (like 50) you go up 50 on the y axis from the y-intercept and over 1 on the x-axis.
Part I: A system of equations can result in 3 possibilities: consistent, inconsistent, and dependent. Discuss each of these types of solution that can be generated, and describe the graph of each possibility.
Part II: Break-Even Analysis and Cost Analysis: As a first-time homeowner, there are going to many decisions that you need to make, such as whom to hire for the upkeep of your lawn. You have just received advertisements from 2 companies in your area: Greener Lawns and Lawns for Less. Greener Lawns charges an initial fee of $200, plus $50 per hour for labor costs. Lawns for Less charges an initial fee of $300, plus $25 per hour for labor costs.
1.If h represents the number of labor hours and C represents the cost, write the total cost equation for Greener Lawns.
2.If h represents the number of labor hours and C represents the cost, write the total cost equation for Lawns for Less.
3.Solve the system of equations for the total cost of lawn care using the desired technique: substitution, elimination, or graphing.
4.Document how you came to these conclusions for accuracy.
Mathematics of Finance
Part III: To purchase your first home, you may be required to borrow funds from a bank. You have just graduated from college, and your dream is to own your first home. Before you begin looking for your dream home, you need to learn more about funding options and the process required to finance a home.
Research online to find more information about home loans and mortgages.
1.Discuss your options for obtaining a home loan and how mortgages work.
2.Discuss the process/procedures for obtaining the loan and the ideal interest rates for home loans.
3.Report your findings in 2 paragraphs.
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Do you need help drawing the lines in the first post? Otherwise, that seems done.
On the second post...
Part I: A consistent solution occurs when the two lines intersect in at least one point. An inconsistent solution when the two lines never intersect (so, they're parallel). A dependent solution is a special kind of consistent solution that occurs when the two lines happen to be the same line and there are infinitely many solutions.
Part II: 1. C = 200 + 50h
2. C = 300 + 25h
3. Use elimination to get: 0 = -100 - 25h --> h = 4
4. I don't need to do this one. If you're required to do it for class, I'd suggest you do it.
Part III: You're on your own for that one. Sounds like a lot of writing...
I'm sorry it seems like I post a wrong problems. I have to poste the whole problem, you can see what equation thatI require to solve the problem is about home loans and break_even
So can you help me to drawing the lines as well if you may
Well the explanation gave you a slope for both lines and a y-intercept for both points. One line has a slope of 50 and a y-intercept at (0, 200) and the other has a slope of 25 and a y-intercept at (0, 300). The equations of these lines are y = 50x + 200 and y = 25x + 300. You should graph one line first and then the other. To graph the first line, choose x = 1 to get y = 250. (0, 200) is already given, so plot that point and (1, 250). Connect the dots to form the first line. To graph the second line, choose x = 1 to get y = 325. (0, 300) is already given, so plot that point and (1, 325). Connect the dots to form the second line.