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  • 5 years ago

i am willing to do all the work, i just dont know where to start. i did find the value of k (1/39 ln 2700/800)= .0902 and i think the exponentiial growth is N(0)=800e.0902t In 1967 a 10 year-old Golden Hawk sold for only $800, and in 2006, this car, was worth about $27,000. Question: Estimate the value of the car in 2008.

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  1. anonymous
    • 5 years ago
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    800=N(0)* e^(10*k) 1st equation 27000=N(0)* e^(49*k) 2nd equation find N(0) and k from above two equations and then use price2008=N(0)*e^(k*51)

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