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anonymous

  • 5 years ago

solution set of absolute value 1-6x-8<-1

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  1. anonymous
    • 5 years ago
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    What parts are in the absolute value? Is it |1-6x|-8<-1?

  2. anonymous
    • 5 years ago
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    yes

  3. anonymous
    • 5 years ago
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    not sure how to do the absolute value things

  4. anonymous
    • 5 years ago
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    On the keyboard its shift and then above the enter key. If you add the 8 to both sides you get: |1-6x|<7 This means 1-6x<7 and 1-6x>-7 Solving for x results in: -6x<6 and -6x>-8 x>-1 and x<4/3 or in interval notation: (-1, 4/3)

  5. anonymous
    • 5 years ago
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    -12<-5x+3<2 i got no solution

  6. anonymous
    • 5 years ago
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    If you subtract 3 from all the terms you get: -15<-5x<-1 Then divide by -5 3>x>1/5 or looking the other way 1/5<x<3 which is (1/5, 3) Remember: if you divide or multiply by a negative number you have to change the direction of the less than and greater than signs.

  7. anonymous
    • 5 years ago
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    I have 2 is less than or equal to 5x+2<17 I got in interval notation [0,3) is that correct

  8. anonymous
    • 5 years ago
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    0 less than or equal to x<3

  9. anonymous
    • 5 years ago
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    Yes!

  10. anonymous
    • 5 years ago
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    thank you I think I am getting it you are a life saver

  11. anonymous
    • 5 years ago
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    Not a problem.

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