anonymous
  • anonymous
solution set of absolute value 1-6x-8<-1
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
What parts are in the absolute value? Is it |1-6x|-8<-1?
anonymous
  • anonymous
yes
anonymous
  • anonymous
not sure how to do the absolute value things

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anonymous
  • anonymous
On the keyboard its shift and then above the enter key. If you add the 8 to both sides you get: |1-6x|<7 This means 1-6x<7 and 1-6x>-7 Solving for x results in: -6x<6 and -6x>-8 x>-1 and x<4/3 or in interval notation: (-1, 4/3)
anonymous
  • anonymous
-12<-5x+3<2 i got no solution
anonymous
  • anonymous
If you subtract 3 from all the terms you get: -15<-5x<-1 Then divide by -5 3>x>1/5 or looking the other way 1/5
anonymous
  • anonymous
I have 2 is less than or equal to 5x+2<17 I got in interval notation [0,3) is that correct
anonymous
  • anonymous
0 less than or equal to x<3
anonymous
  • anonymous
Yes!
anonymous
  • anonymous
thank you I think I am getting it you are a life saver
anonymous
  • anonymous
Not a problem.

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