anonymous
  • anonymous
Hi I am 55 years old and I have had to back school I am trying to figure out fractions is there anyone out there that can help my test is Monday HELP
Mathematics
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anonymous
  • anonymous
Hi I am 55 years old and I have had to back school I am trying to figure out fractions is there anyone out there that can help my test is Monday HELP
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
If you have a concrete problem you need help with this site is real good for that, but for a loose subject like fractions I really recommend this site, it's excellent. http://www.purplemath.com/modules/
anonymous
  • anonymous
thank you but will this get me to the answers i like right now?
anonymous
  • anonymous
Like I said, if you got a specific problem/question, bring it on. If not, spend 20min on purplemath (fractions part) and you will have learned alot.

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anonymous
  • anonymous
I am having more problems then I can tell you, right now all I am trying to is get the answer to 81/4+121/2+91/3= I have not been in school since 1983
anonymous
  • anonymous
sorry all i am trying to is figure out how to brake this down to the lowest terms
anonymous
  • anonymous
Is it (81/4 + 121/2) all divided by 3?
anonymous
  • anonymous
Your thought process should be this: How can I change these fractions so I can just add them together? The answer is this: The lowest common integer that binds 4 3 and 2. 4*3=12 3*4=12 2*6=12 So to keep the same value on these integers you must keep the ratio. Thereby you multiply the numbers like this: (81/4)*(3/3) (121/2)*(6/6) (91/3)*(4/4) See what I did?

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