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anonymous

  • 5 years ago

hey there i have difficulty with augmented matrix ... can anybody help me with that?

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  1. anonymous
    • 5 years ago
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    sure, what's up?

  2. anonymous
    • 5 years ago
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    system: x-4y+3z=5 -x+3y- z=-3 2x -4z=6

  3. anonymous
    • 5 years ago
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    1 3 2 / 1 0 1 -2 /5 0 0 4 /4

  4. anonymous
    • 5 years ago
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    not is not a system

  5. anonymous
    • 5 years ago
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    coefficient matrix 1 -4 3 -1 3 -1 2 0 -4

  6. anonymous
    • 5 years ago
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    augmented matrix 1 -4 3 5 -1 3 -1 -3 2 0 -4 6

  7. anonymous
    • 5 years ago
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    is that the answer?

  8. anonymous
    • 5 years ago
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    no, that's an example, I'm not sure what your question is. you just typed in a matrix.

  9. anonymous
    • 5 years ago
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    your augmented matrix is derived from the coefficients and constant terms of your system of linear equations

  10. anonymous
    • 5 years ago
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    is that the answer?

  11. anonymous
    • 5 years ago
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    do youwant me to write u the whole question maybe u gonna understant ??

  12. anonymous
    • 5 years ago
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    yes. are you given a system of linear equations & asked to write an augmented matrix?

  13. anonymous
    • 5 years ago
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    find X, where x=(x1,x2,x3)to the power of t, given the A is known (3*) matrix, b a known column matrix, and that the system Ax=b has augmented matrix equivalent to

  14. anonymous
    • 5 years ago
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    1 3 2 ! -1 0 1 -2 ! 5 0 0 4 ! 4

  15. anonymous
    • 5 years ago
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    thats is the qustion

  16. anonymous
    • 5 years ago
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    question sorry

  17. anonymous
    • 5 years ago
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    haha, yeah, sorry mattheos, that is a little more in depth than just having difficulty with an augmented matrix. i'm in my first semester of linear algebra & i haven't seen a problem like that yet.

  18. anonymous
    • 5 years ago
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    aham ok ... thx anyway

  19. anonymous
    • 5 years ago
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    I'm going to repost your question if you don't mind, I would like to see a solution as well, I could solve this if it didn't involve the power of t.

  20. anonymous
    • 5 years ago
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    Do you have to use gaussian elimination?

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