At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
= 0 ?
56s^2+23s-63 = 0?
Nope have to factor this out. I know the common denominator is 7 but I get lost and confused after that .
oh just use the discriminant..
D = b^2 - 4ac
(7s+9)(8x-7) if I did it right.
Ok this is what I get 56s^2+23s-63 (56s+ )(s- )
oops I meant for the second one to be an s as well
D = 529 + 14112
Now got to figure out what the numbers are for the remaining. I know that 9*7 is 63 But when you work it into the problem and then use the foil method I dont get the 23s in the middle Have also tried 12*3
x1 = (- 23 - 121)/(2*56) = 9/7
x2 = (- 23 + 121)/(2*56) = 7/8
TBates you rock!!!!!
I used the quadratic equation to find one of the zeros and worked backwards to get the factors.
Thank you thank you thank you !
well that's what i suggested.. wasn't it?
(x - 9/7)(x - 7/8)
That it is. The quadratic formula will always work!
yes it was you were correct as well