anonymous
  • anonymous
56s^2+23s-63 Need help solving this one
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
bahrom7893
  • bahrom7893
= 0 ?
bahrom7893
  • bahrom7893
56s^2+23s-63 = 0?
anonymous
  • anonymous
Nope have to factor this out. I know the common denominator is 7 but I get lost and confused after that .

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bahrom7893
  • bahrom7893
oh just use the discriminant..
bahrom7893
  • bahrom7893
D = b^2 - 4ac
anonymous
  • anonymous
(7s+9)(8x-7) if I did it right.
anonymous
  • anonymous
Ok this is what I get 56s^2+23s-63 (56s+ )(s- )
anonymous
  • anonymous
oops I meant for the second one to be an s as well
bahrom7893
  • bahrom7893
D = 529 + 14112
anonymous
  • anonymous
Now got to figure out what the numbers are for the remaining. I know that 9*7 is 63 But when you work it into the problem and then use the foil method I dont get the 23s in the middle Have also tried 12*3
bahrom7893
  • bahrom7893
x1 = (- 23 - 121)/(2*56) = 9/7
anonymous
  • anonymous
(7s+9)(8s-7)
bahrom7893
  • bahrom7893
x2 = (- 23 + 121)/(2*56) = 7/8
anonymous
  • anonymous
TBates you rock!!!!!
anonymous
  • anonymous
I used the quadratic equation to find one of the zeros and worked backwards to get the factors.
anonymous
  • anonymous
Thank you thank you thank you !
bahrom7893
  • bahrom7893
well that's what i suggested.. wasn't it?
bahrom7893
  • bahrom7893
(x - 9/7)(x - 7/8)
anonymous
  • anonymous
That it is. The quadratic formula will always work!
anonymous
  • anonymous
yes it was you were correct as well

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