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anonymous

  • 5 years ago

56s^2+23s-63 Need help solving this one

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  1. bahrom7893
    • 5 years ago
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    = 0 ?

  2. bahrom7893
    • 5 years ago
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    56s^2+23s-63 = 0?

  3. anonymous
    • 5 years ago
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    Nope have to factor this out. I know the common denominator is 7 but I get lost and confused after that .

  4. bahrom7893
    • 5 years ago
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    oh just use the discriminant..

  5. bahrom7893
    • 5 years ago
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    D = b^2 - 4ac

  6. anonymous
    • 5 years ago
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    (7s+9)(8x-7) if I did it right.

  7. anonymous
    • 5 years ago
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    Ok this is what I get 56s^2+23s-63 (56s+ )(s- )

  8. anonymous
    • 5 years ago
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    oops I meant for the second one to be an s as well

  9. bahrom7893
    • 5 years ago
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    D = 529 + 14112

  10. anonymous
    • 5 years ago
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    Now got to figure out what the numbers are for the remaining. I know that 9*7 is 63 But when you work it into the problem and then use the foil method I dont get the 23s in the middle Have also tried 12*3

  11. bahrom7893
    • 5 years ago
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    x1 = (- 23 - 121)/(2*56) = 9/7

  12. anonymous
    • 5 years ago
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    (7s+9)(8s-7)

  13. bahrom7893
    • 5 years ago
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    x2 = (- 23 + 121)/(2*56) = 7/8

  14. anonymous
    • 5 years ago
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    TBates you rock!!!!!

  15. anonymous
    • 5 years ago
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    I used the quadratic equation to find one of the zeros and worked backwards to get the factors.

  16. anonymous
    • 5 years ago
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    Thank you thank you thank you !

  17. bahrom7893
    • 5 years ago
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    well that's what i suggested.. wasn't it?

  18. bahrom7893
    • 5 years ago
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    (x - 9/7)(x - 7/8)

  19. anonymous
    • 5 years ago
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    That it is. The quadratic formula will always work!

  20. anonymous
    • 5 years ago
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    yes it was you were correct as well

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