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anonymous
 5 years ago
How do you find the acceleration of two objects if the coefficient of kinetic friction between the 7kg object and the plane is 0.250? Given: m1=7kg, m2=12kg, and there is an angle of 37.0 degrees.
anonymous
 5 years ago
How do you find the acceleration of two objects if the coefficient of kinetic friction between the 7kg object and the plane is 0.250? Given: m1=7kg, m2=12kg, and there is an angle of 37.0 degrees.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need more information. What does the setup look like?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay. There is a triangle, with a 37 degree angle in the left bottom corner, holding up a block that weighs 7kg. This block is attached to a levy on the right upper corner of the triangle which is holding up a 12 kg block hanging downward on the right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First draw a free body diagram. For the 7kg object you should get the two equations: Fx=TFfmgsin37=m1a and Fy=Nmgcos37=0. So N=mgcos37=54.79. The friction force(Ff)=.25N=13.7. Substitute this into Fx and you will get Fx=T54.98=m1a. This is the same as T=m1a+54.98. Then from the 12kg object, you should get the equation: Fy=m2gT=m2a. Which is the same as T=m2gm2a. Substitute this in for the T in the Fx equation and solve for a. I got 2.76, but I may have done some math wrong somewhere, so you should probably check everything :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'll try it our right now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did you get 13.7 from the friction force?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The normal force is mgcos37 which is 54.79. Friction force is normal force time the coeffecient of friction. So it is 54.79*.25= 13.7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got up to the last step. m2gm2a= m1a + 55.0N 118N12kg(a)= 7kg+55.0N How would I solve this? :?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, I got it. Thank you again!
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