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anonymous

  • 5 years ago

Use the equation given below to find f '' (π/3). f (x) = sec(x)

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  1. anonymous
    • 5 years ago
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    first find f'(x) this is sec(x)tan(x). then find f''(x). you have to use the product rule to find the second derivative: take the derivative of sec(x) * tan(x) + the derivative of tan(x)*sec(x). once you have this you can just plug in pi/3 and solve.

  2. anonymous
    • 5 years ago
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    i got 48 but it showed my answer as wrong

  3. anonymous
    • 5 years ago
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    what did you get from the product rule?

  4. anonymous
    • 5 years ago
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    f'g+fg'

  5. anonymous
    • 5 years ago
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    I got sec(x)tan(x)tan(x) + sec(x)sec^2(x).

  6. anonymous
    • 5 years ago
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    ... do the product rule and tell me what you get.

  7. anonymous
    • 5 years ago
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    The is because Sec'(x) is sec(x)tan(x) and tan'(x) is sec^2(x)

  8. anonymous
    • 5 years ago
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    how do i find sec^2(pi/3)

  9. anonymous
    • 5 years ago
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    it is the same as sec(pi/3)sec(pi/3) so you should get 2*2

  10. anonymous
    • 5 years ago
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    i got 14

  11. anonymous
    • 5 years ago
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    is that correct?

  12. anonymous
    • 5 years ago
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    hmmm i got 11. so sec(pi/3) is 2 and tan(pi/3) is (SQRT3)/2. So I got 2*(SQRT3)/2*(SQRT3)/2 + 2*2*2 this simplifies to 3 +8 which is 11

  13. anonymous
    • 5 years ago
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    WAIT thats wrong....

  14. anonymous
    • 5 years ago
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    it should be 3/2 + 8

  15. anonymous
    • 5 years ago
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    isnt tan pi/3 just SQRT 3?

  16. anonymous
    • 5 years ago
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    so you would 2*sqrt 3*sqrt3+2*2*2

  17. anonymous
    • 5 years ago
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    oops yes you're right, sorry my trig isnt so great

  18. anonymous
    • 5 years ago
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    lol thats ok

  19. anonymous
    • 5 years ago
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    so does make it 14?

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