anonymous
  • anonymous
How do I get the derivative of ln(x^2)?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
2/x
anonymous
  • anonymous
why though? isn't it the chain rule?
anonymous
  • anonymous
yes. d(ln u)/dx = 1/u(du/dx). So [1/(x^2)]*2x which simplifies to 2/x.

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anonymous
  • anonymous
outer function: ln() inner function: x^2 ... d(outer function) = 1/x d(inner function) = 2x 1/x * x^2 * 2x = 2x^2 ???
anonymous
  • anonymous
the d(outer function)= 1/(x^2) not 1/x.

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