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anonymous

  • 5 years ago

5^log(base x)5 = x^3

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  1. anonymous
    • 5 years ago
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    first, by definition of logarithms, this is the same as writing \[\log_x(5) = \log_5(x^3)\] From here, we can use the fact that \[\log_b(a) = \frac{\ln(a)}{\ln(b)}\] to simplify: \[\frac{\ln(5)}{\ln(x)} = \frac{\ln(x^3)}{\ln(5)}\] From here, you just need to solve for x.

  2. anonymous
    • 5 years ago
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    which i would multiply both 5's, and have it like so:

  3. anonymous
    • 5 years ago
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    \[\ln(5)*\ln(5)/lnx*lnx^3\]

  4. anonymous
    • 5 years ago
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    is that right?

  5. anonymous
    • 5 years ago
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    Do you mean \[\ln(5)^2 = \ln(x)*\ln(x^3)\]? Then, remember that \[ln(x^3)\] is the same thing as \[3*\ln(x)\], so we have \[\ln(5)^2 = 3\ln(x)^2\] and from there solving should be simple.

  6. anonymous
    • 5 years ago
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    can you get on http://www.twiddla.com/503175 and explain please?

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