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anonymous

  • 5 years ago

x2 + 8x + 12 = 0

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  1. anonymous
    • 5 years ago
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    x = -2; x = -6 x = -2; x = 6 x = 2; x = 6 x = 2; x = -6

  2. anonymous
    • 5 years ago
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    whichh one?

  3. anonymous
    • 5 years ago
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    x=-6,-2

  4. anonymous
    • 5 years ago
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    so your first one

  5. anonymous
    • 5 years ago
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    thanks!

  6. anonymous
    • 5 years ago
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    (x + 7) (x - 15) = 0

  7. anonymous
    • 5 years ago
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    The quadratic factors as (x+6)(x+2)=0 so the solutions are x=-6 or x=-2.

  8. anonymous
    • 5 years ago
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    x = -7; x = 15 x = -7 x = 15 x = 7; x = -15

  9. anonymous
    • 5 years ago
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    which one

  10. anonymous
    • 5 years ago
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    You need an equation first

  11. anonymous
    • 5 years ago
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    (x + 7) (x - 15) = 0

  12. anonymous
    • 5 years ago
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    same thing as above: x=-7 and x=15

  13. anonymous
    • 5 years ago
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    x=-7 or x=15...they're both solutions.

  14. anonymous
    • 5 years ago
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    x2 + 5x = 6 x = 1; x = -6 x = -1; x = -6 x = -1; x = 6 x = 1; x = 6

  15. anonymous
    • 5 years ago
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    x=-6,1 x=-6,x=-1

  16. anonymous
    • 5 years ago
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    A,B,C,D?

  17. anonymous
    • 5 years ago
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    Smitty - when you factor as ( )( ) = 0, it means either the first factor is zero, the second is zero or they're both zero. The equation's true then for those x-values that make a factor equal to zero. x2 + 5x - 6 =0 -> (x+6)(x-1)=0 so the answer is x = -6 or x = 1.

  18. anonymous
    • 5 years ago
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    x = -1; x = -6 B!

  19. anonymous
    • 5 years ago
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    x(x - 8) = 9 x = -1; x = 9 x = -1; x = -9 x = 1 x = 1; x = -9

  20. anonymous
    • 5 years ago
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    x=-1,9 A

  21. anonymous
    • 5 years ago
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    Smitty, you have to expand the left-hand side, subtract 9 from both sides and either factorize or complete the square or use the quadratic equation to figure out x.

  22. anonymous
    • 5 years ago
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    x2 - 4 = 0 x = 2; x = -2 x = -2 no solutions x = 2

  23. anonymous
    • 5 years ago
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    x = +2 or -2

  24. anonymous
    • 5 years ago
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    x=2

  25. anonymous
    • 5 years ago
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    (x + 6) (5x - 3) 5x2 - 27x - 18 5x2 + 30x - 18 5x2 + 27x - 18 5x2 + 27x + 18

  26. anonymous
    • 5 years ago
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    sorry accidently hit enter early x = 2, -2

  27. anonymous
    • 5 years ago
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    i got it wrong haha ohwell

  28. anonymous
    • 5 years ago
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    5x^2+27x-18

  29. anonymous
    • 5 years ago
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    x2 - 10x + 21 = 0 x = 3; x = -7 x = 3; x = 7 x = -3; x = 7 x = -3; x = -7

  30. anonymous
    • 5 years ago
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    x=3,7 B

  31. anonymous
    • 5 years ago
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    x2 - 4 = 0 x = 2; x = -2 x = 2 no solutions x = -2 9. Multiply the binomials: (3x + 4) (5x - 4) 15x2 + 8x - 16 15x2 + 8x + 16 15x2 + 20x - 16 15x2 - 8x - 16 10. Find the solution(s) for x: x2 + 7x + 10 = 0 x = -2; x = 5 x = 2; x = 5 x = 2; x = -5 x = -2; x = -5 Session Complete

  32. anonymous
    • 5 years ago
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    x2 - 4 = 0 x = 2; x = -2 x = 2 no solutions x = -2

  33. anonymous
    • 5 years ago
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    Ok well I can't do all of your hw for you. sorry

  34. anonymous
    • 5 years ago
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    just one more?

  35. anonymous
    • 5 years ago
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    Ok choose 1!

  36. anonymous
    • 5 years ago
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    what?

  37. anonymous
    • 5 years ago
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    thanks for all theeee help before

  38. anonymous
    • 5 years ago
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    I can do one more but only one more and no problem

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