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anonymous
 5 years ago
x2 + 8x + 12 = 0
anonymous
 5 years ago
x2 + 8x + 12 = 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x = 2; x = 6 x = 2; x = 6 x = 2; x = 6 x = 2; x = 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The quadratic factors as (x+6)(x+2)=0 so the solutions are x=6 or x=2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x = 7; x = 15 x = 7 x = 15 x = 7; x = 15

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need an equation first

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0same thing as above: x=7 and x=15

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=7 or x=15...they're both solutions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x2 + 5x = 6 x = 1; x = 6 x = 1; x = 6 x = 1; x = 6 x = 1; x = 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Smitty  when you factor as ( )( ) = 0, it means either the first factor is zero, the second is zero or they're both zero. The equation's true then for those xvalues that make a factor equal to zero. x2 + 5x  6 =0 > (x+6)(x1)=0 so the answer is x = 6 or x = 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x(x  8) = 9 x = 1; x = 9 x = 1; x = 9 x = 1 x = 1; x = 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Smitty, you have to expand the lefthand side, subtract 9 from both sides and either factorize or complete the square or use the quadratic equation to figure out x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x2  4 = 0 x = 2; x = 2 x = 2 no solutions x = 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x + 6) (5x  3) 5x2  27x  18 5x2 + 30x  18 5x2 + 27x  18 5x2 + 27x + 18

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry accidently hit enter early x = 2, 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got it wrong haha ohwell

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x2  10x + 21 = 0 x = 3; x = 7 x = 3; x = 7 x = 3; x = 7 x = 3; x = 7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x2  4 = 0 x = 2; x = 2 x = 2 no solutions x = 2 9. Multiply the binomials: (3x + 4) (5x  4) 15x2 + 8x  16 15x2 + 8x + 16 15x2 + 20x  16 15x2  8x  16 10. Find the solution(s) for x: x2 + 7x + 10 = 0 x = 2; x = 5 x = 2; x = 5 x = 2; x = 5 x = 2; x = 5 Session Complete

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x2  4 = 0 x = 2; x = 2 x = 2 no solutions x = 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok well I can't do all of your hw for you. sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks for all theeee help before

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can do one more but only one more and no problem
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