anonymous 5 years ago Find the dicontinuites of any: 1. f(x) = sin(x^2 - 2) 2. f(x) = 1/(1 - 2sinx)

1. anonymous

can you please describe why because i don't understand discontinuites

2. anonymous

discontinuites*

3. anonymous

Discontinuities happen when the function is undefined for some reason. The biggest ones are when the denominator is zero, or you have a negative number under a square root. Since sine is defined for ANY number you plug in, there are no discontinuities for the first one. For the second one, we have an expression involving x in the denominator, so that should throw up a red flag. The function will be discontinuous when the denominator is 0 (since this would make the function go to infinity, which is undesirable...), and this happens when $1-2\sin(x) = 0$, or when $\sin(x) = \frac{1}{2}$ Now just solve for x, and you'll be done!