anonymous
  • anonymous
The width of a rectangle is 8 inches less than one-half of its length. If the perimeter of the rectangle is 38 inches, find the area of the rectangle.
Mathematics
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anonymous
  • anonymous
The width of a rectangle is 8 inches less than one-half of its length. If the perimeter of the rectangle is 38 inches, find the area of the rectangle.
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
If the length is x, then the width would be (x/2-8) Perimeter = x + x +(x/2-8) + (x/2-8) 38=2x +x -16 Solve for x and you get x = 18 inches. Length = x = 18 inches Width = (x/2-8) = 1 inches Area of a rectangle is length times width Area =\[18\times1\]=18 inches squared.

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