## anonymous 5 years ago find the equation of the tangent line to the graph of y=sqrt x/x+1 at point where x=1

1. anonymous

Step 1.)Plug in x =1 in the equation and find the y-coordinate. Step 2.)Take the derivative and evaluate it at x = 1. This will be your m in the next step. Once you have these two things, use y=mx+b or $y-y _{1}=m(x-x _{1})$ to find the equation of the tangent line.

2. anonymous

im having a tough time finding the derivative for the equation, any way you could help?

3. anonymous

Could you re-write the equation properly? :D

4. anonymous

$y=\sqrt{x}\div x+1$

5. anonymous

$y=\sqrt{x}/(x+1)$ is that the equation?

6. anonymous

yes

7. anonymous

This will be the derivative. $(1-x)/(2(\sqrt(x)(x+1)^2)$