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anonymous
 5 years ago
find the equation of the tangent line to the graph of y=sqrt x/x+1 at point where x=1
anonymous
 5 years ago
find the equation of the tangent line to the graph of y=sqrt x/x+1 at point where x=1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Step 1.)Plug in x =1 in the equation and find the ycoordinate. Step 2.)Take the derivative and evaluate it at x = 1. This will be your m in the next step. Once you have these two things, use y=mx+b or \[yy _{1}=m(xx _{1})\] to find the equation of the tangent line.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im having a tough time finding the derivative for the equation, any way you could help?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Could you rewrite the equation properly? :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=\sqrt{x}\div x+1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=\sqrt{x}/(x+1)\] is that the equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This will be the derivative. \[(1x)/(2(\sqrt(x)(x+1)^2)\]
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