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anonymous

  • 5 years ago

find the equation of the tangent line to the graph of y=sqrt x/x+1 at point where x=1

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  1. anonymous
    • 5 years ago
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    Step 1.)Plug in x =1 in the equation and find the y-coordinate. Step 2.)Take the derivative and evaluate it at x = 1. This will be your m in the next step. Once you have these two things, use y=mx+b or \[y-y _{1}=m(x-x _{1})\] to find the equation of the tangent line.

  2. anonymous
    • 5 years ago
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    im having a tough time finding the derivative for the equation, any way you could help?

  3. anonymous
    • 5 years ago
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    Could you re-write the equation properly? :D

  4. anonymous
    • 5 years ago
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    \[y=\sqrt{x}\div x+1\]

  5. anonymous
    • 5 years ago
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    \[y=\sqrt{x}/(x+1)\] is that the equation?

  6. anonymous
    • 5 years ago
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    yes

  7. anonymous
    • 5 years ago
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    This will be the derivative. \[(1-x)/(2(\sqrt(x)(x+1)^2)\]

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