anonymous
  • anonymous
I asked this yesterday and had no replies. The gross national product of a certain country is N(t)=t^2+3t+121 billion dollars where t is the number of years after 1990. At what percentage rate will the GNP be changing with respect to time in 1995? I got 13%, is this correct?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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sgadi
  • sgadi
given that t=5 so GNP=161 The rate of increase of GNP is \[\frac{dGNP}{dt}=2t+3=13\] there fore percentage increase is \[\frac{13}{161}100=8.0745\%\]
anonymous
  • anonymous
How do you get GNP=161
sgadi
  • sgadi
I am sorry ..... i did a mistake GNP=t^2+3t+12=5^2+3*5+12=52 so, 13/52*100=25%

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anonymous
  • anonymous
the problem is t^2+3t+121 not 12 i took the derivative of this equation which is 2t+3 then t(5) then I get 13.
sgadi
  • sgadi
then my first reply is correct .... GNP=t^2+3t+12=5^2+3*5+12=161 so, 13/161*100=8.0745%
anonymous
  • anonymous
but where do you get 161
sgadi
  • sgadi
from the given formula .... also given time = t= 1995-1990=5 gross national product (GNP) = t^2+3t+121 =5^2+3*5+121=161
anonymous
  • anonymous
ok i guess i should replace the t(5) with the original problem and the problem after I take the derivative.
sgadi
  • sgadi
yes ....
anonymous
  • anonymous
Thank You

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