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anonymous
 5 years ago
how do you factor trinomials
anonymous
 5 years ago
how do you factor trinomials

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can use pascal's triangle or the binomial theorem or by factoring the first two and the second two and seeing if a common factor emerges...its kind of hard to explain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know my teacher cant even do it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha do you have a specific problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah I just dont know how to do exponents on the computer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can use the equation button down on the left of just do shift 6 its the ^ which means exponent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02x squared 14x  36 we have to do polynomials in the x squared+ bx +c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so you have \[2x ^{2}  14x  36 =0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no we have to pull the lowest number and the lowest variable then divide each term by that so I know its @ because they all dont have a common variable then divide each term by 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry the @ is suppose to be 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so notice all the coefficients can be factored out a 2 so you have\[ (x ^{2}  7x  16) = 0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops its \[2 (x ^{2}  7x  18) = 0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah thats what I got but then I have to find the factors of 18 and then im lost

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah ok. so the trick is to find two numbers that add up to 7 but when multiplied together equal 18

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it would be 2 and 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so look at 9 and 2. 9*2 = 18 but you want one to be negative so you have 18 and you want them to add to 7. so try 9*2 = 18 and 9 + 2 = 7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but then what do you do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0something like ( x9) ( x+2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so now you factor them you know one is 9 and one is 2 so you subtract them from x. you get (x2)(x+9)=0 and by FOILing you get x^2 7x 18 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha sorry i mean that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you have your roots, x=2, x=9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does it matter which one goes where can I switch them and get the samething

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no it does matter if you had what i put you'd have (x2)(x+9) = 0 and you get x^2 + 7x  18 which is not correct. the answer is x =2, x = 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in the back of the book its 2(x+2) (x9)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh you were just factoring? sorry i thought you were solving. yeah we factored out the 2 remember? we have to bring it back in so mulitply it by what you told me and its the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was solving two but I got as far as the last part. Do you mind helping me on another?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^3+6x^2+16x I have to solve and factor

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got x(x^2+6x+16) is that right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah you could do that but it might be easier to factor out a negative. just so its a little simpler to look at. so you could just have x(x^2 6x  16)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so are the factors then 2 and 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure? 8 + 2 = 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no switch the signs. then you have 8 and 2 which 8*2 = 16 and 8 + 2 = 6 which is what we want

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how do you pull a number or variable from 4y45+y^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok you can't since you have to see that there is no coefficient on y^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what I thought but in the back of the book it says (y5) (y+9)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0think of some basic multiples of 45 ...one to try is 5 since 45 ends in 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rearrange the polynomial...its really y^2 + 4y  45

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so all you have to do is factor in a problem like that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so are you doing the same thing with x^272+6x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah exactly the same. sometimes if it helps you to see it you should rewrite it in the form ax^2 + bx + c to see it. if you can already see it then it doesnt matter.
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