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I know my teacher cant even do it

haha do you have a specific problem?

yeah I just dont know how to do exponents on the computer

you can use the equation button down on the left of just do shift 6 its the ^ which means exponent

2x squared- 14x - 36
we have to do polynomials in the x squared+ bx +c

ok so you have \[2x ^{2} - 14x - 36 =0\]

sorry the @ is suppose to be 2

ok so notice all the coefficients can be factored out a 2 so you have\[ (x ^{2} - 7x - 16) = 0\]

yeah good

oops its \[2 (x ^{2} - 7x - 18) = 0\]

yeah thats what I got but then I have to find the factors of 18 and then im lost

so it would be 2 and 9

yeah good job

but then what do you do?

something like ( x-9) ( x+2)

oops
YES

haha sorry i mean that

you are correct

then you have your roots, x=2, x=-9

does it matter which one goes where can I switch them and get the samething

so whats the answer

those are your roots

in the back of the book its 2(x+2) (x-9)

I was solving two but I got as far as the last part. Do you mind helping me on another?

sure

-x^3+6x^2+16x I have to solve and factor

I got x(-x^2+6x+16) is that right?

so are the factors then -2 and 8

are you sure? 8 + -2 = 6

yeah isnt it?

no switch the signs. then you have -8 and 2 which -8*2 = -16 and -8 + 2 = -6 which is what we want

oh we need -6

so how do you pull a number or variable from 4y-45+y^2

ok you can't since you have to see that there is no coefficient on y^2

thats what I thought but in the back of the book it says (y-5) (y+9)

think of some basic multiples of 45 ...one to try is 5 since 45 ends in 5

rearrange the polynomial...its really y^2 + 4y - 45

so all you have to do is factor in a problem like that

yeah thats it

so are you doing the same thing with x^2-72+6x