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anonymous
 5 years ago
find the arc length of f(x)=x^2/2
anonymous
 5 years ago
find the arc length of f(x)=x^2/2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is a formula for arc length involving an integral that I don't want to type out. However, you do need to find the derivative of f, which in this case is just x. Then plug into your formula for arc length and chug it through the integral. Fan me if this helps. Thanks :p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have the formula but i had trouble solving it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok to solve whats in the integral, you need to use trig substitutions. Did you learn trig substitutions in class? So in this case, I would substitute x=secθ

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have to find the derivative first, not the integral

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah the derivative is x like i said before

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Bring down the power, which is 2, and that cancels out with the 2 as the denominator. So you are left with x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this what i did x^2/2> 2^1x^2>4^1X

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02^1x^2>4^1X this is an error. Because 2^1(2^1)=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When you multiply two numbers with same base, then you add the exponent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is very tricky lol, i dint even notice it. if i get stuck ill post. please check to c if i need help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sure. But make sure you fan me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0forsure:) im going to do it rightnow

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey im soo stuck can you click on the link to help me http://www.twiddla.com/505875
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