find the arc length of f(x)=x^2/2

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find the arc length of f(x)=x^2/2

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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There is a formula for arc length involving an integral that I don't want to type out. However, you do need to find the derivative of f, which in this case is just x. Then plug into your formula for arc length and chug it through the integral. Fan me if this helps. Thanks :p
i have the formula but i had trouble solving it
oh ok to solve whats in the integral, you need to use trig substitutions. Did you learn trig substitutions in class? So in this case, I would substitute x=secθ

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i have to find the derivative first, not the integral
Yeah the derivative is x like i said before
isn't it x/4
Bring down the power, which is 2, and that cancels out with the 2 as the denominator. So you are left with x
this what i did x^2/2--> 2^-1x^2--->4^-1X
2^-1x^2--->4^-1X this is an error. Because 2^-1(2^1)=2
Ooops I mean 1
not 2
When you multiply two numbers with same base, then you add the exponent
that is very tricky lol, i dint even notice it. if i get stuck ill post. please check to c if i need help
Sure. But make sure you fan me
forsure:) im going to do it rightnow
i did it
hey im soo stuck can you click on the link to help me http://www.twiddla.com/505875

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