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anonymous
 5 years ago
Bill's upstream canoe trip took 2 hours longer than the return trip. If he averaged 2 mph on the upstream trip and 6 mph on the return trip, then how long was the upstream trip?
anonymous
 5 years ago
Bill's upstream canoe trip took 2 hours longer than the return trip. If he averaged 2 mph on the upstream trip and 6 mph on the return trip, then how long was the upstream trip?

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sandra
 5 years ago
Best ResponseYou've already chosen the best response.01. u = d + 2 And given they're the same distance: 2. u*2 = d*6 now substitute d+2 for u in the second equation: (d+2)*2 = d*6 2d + 4 = 6d 4 = 6d2d 4 = 4d d= 1. The downstream trip took 1 hour
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