anonymous
  • anonymous
how do find the derivative of r/(sqrt of r^2 +4)
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
use the derivative for division rule: f(x)/g(x) = f'(x)g(x)-f(x)g'(x)/g(x)^2
anonymous
  • anonymous
i tried that but i keep getting the wrong answer
anonymous
  • anonymous
= (sqrt of r^2 +4) - r(1/2)(2r)(r^2+4)^-1/2/r^2+4

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anonymous
  • anonymous
=(r^2+4 - r^2) /(r^2+4)^3/2
anonymous
  • anonymous
=4 /(r^2+4)^3/2
anonymous
  • anonymous
o i see my mistake i put for the second part (r^2+4)^-3/2
anonymous
  • anonymous
the final answer is =4 /(r^2+4)^3/2
anonymous
  • anonymous
could you became my fan?
anonymous
  • anonymous
im still confused on the part (sqrt of r^2 +4) - r(1/2)(2r)(r^2+4)^-1/2/r^2+4
anonymous
  • anonymous
how did u get (r^2+4)^-1/2
anonymous
  • anonymous
i kept getting it to the power of -3/2
anonymous
  • anonymous
ok... when we derivative a function we always do this for example: the derivative of x^1/2 = 1/2(x)^(1/2-1) = 1/2(x)^-1/2
anonymous
  • anonymous
apply that for you example: the derivative of (r^2+4)^1/2 = (1/2)(2r)(r^2+4)^(1/2-1) = (r)(r^2+4)^(-1/2)
anonymous
  • anonymous
do you get it?
anonymous
  • anonymous
ooooooooooooo
anonymous
  • anonymous
hahaha ok i get it!! THANK YOU!!!
anonymous
  • anonymous
your welcome!

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