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anonymous

  • 5 years ago

how do find the derivative of r/(sqrt of r^2 +4)

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  1. anonymous
    • 5 years ago
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    use the derivative for division rule: f(x)/g(x) = f'(x)g(x)-f(x)g'(x)/g(x)^2

  2. anonymous
    • 5 years ago
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    i tried that but i keep getting the wrong answer

  3. anonymous
    • 5 years ago
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    = (sqrt of r^2 +4) - r(1/2)(2r)(r^2+4)^-1/2/r^2+4

  4. anonymous
    • 5 years ago
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    =(r^2+4 - r^2) /(r^2+4)^3/2

  5. anonymous
    • 5 years ago
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    =4 /(r^2+4)^3/2

  6. anonymous
    • 5 years ago
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    o i see my mistake i put for the second part (r^2+4)^-3/2

  7. anonymous
    • 5 years ago
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    the final answer is =4 /(r^2+4)^3/2

  8. anonymous
    • 5 years ago
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    could you became my fan?

  9. anonymous
    • 5 years ago
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    im still confused on the part (sqrt of r^2 +4) - r(1/2)(2r)(r^2+4)^-1/2/r^2+4

  10. anonymous
    • 5 years ago
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    how did u get (r^2+4)^-1/2

  11. anonymous
    • 5 years ago
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    i kept getting it to the power of -3/2

  12. anonymous
    • 5 years ago
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    ok... when we derivative a function we always do this for example: the derivative of x^1/2 = 1/2(x)^(1/2-1) = 1/2(x)^-1/2

  13. anonymous
    • 5 years ago
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    apply that for you example: the derivative of (r^2+4)^1/2 = (1/2)(2r)(r^2+4)^(1/2-1) = (r)(r^2+4)^(-1/2)

  14. anonymous
    • 5 years ago
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    do you get it?

  15. anonymous
    • 5 years ago
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    ooooooooooooo

  16. anonymous
    • 5 years ago
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    hahaha ok i get it!! THANK YOU!!!

  17. anonymous
    • 5 years ago
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    your welcome!

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spraguer (Moderator)
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