anonymous
  • anonymous
when integrating to find surface area, the usual equations per rotating x-axis or y-axis are the limits of 2(pi)y ds or 2(pi)x ds, however, what about when rotating it around a line eg (x=2) or (y=2)?
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
In the case of rotating about a line parallel to the x-axis, and therefore using 2(pi)y, you have to adjust the y-value (here, the height of the frustrum used to generate the surface area). So, if you have to rotate about y=2, you would have to adjust your element of surface area as \[2\pi(y-2)ds\]Similarly for rotating about the line x=2, parallel to the y-axis. Hope it helps.
anonymous
  • anonymous
thanks =)

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