Gina
  • Gina
help me please!!,,,to the plate plane air capacitor applied potential difference U = 500V in the area of ​​the plates with a = 200 cm square, the distance between d1 = 1,5 mm. plates moved apart to a distance d2 = 15mm. find the energy E1 and E2 of the capacitor before and after razdvizheniya plates, if the source of EMF to razdvizheniem: 1) switched off, and 2) does not turn off. (1) E1 = 14,8 mJ, E2 = 148mkdzh; 2) E1 = 14,8 mJ: E2 = 1,48 mJ
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

sgadi
  • sgadi
can you explain what is "razdvizheniem"
Gina
  • Gina
that is supposed to the word( motion),,,i translated from russian to english
sgadi
  • sgadi
you have given answer also ... you need procedure ... right ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Gina
  • Gina
yes,plesae
sgadi
  • sgadi
answers are in milli J or in micro J .... coz ... I am getting answers in micro J
Gina
  • Gina
\[\int\limits_{o}^{a}d _{x}\]
Gina
  • Gina
what is important is the procedure os can you show me ?
sgadi
  • sgadi
I am typing ... I will send in few minutes ..
Gina
  • Gina
o right
sgadi
  • sgadi
Formulas required \[C=\epsilon_0\frac{A}{d}\] \[Q=CV\] \[E=\frac{1}{2}CV^2\] given \[A=200 cm^2 = 0.02 m^2\] \[d_1=1.5 mm= 1.5e-3 m\] \[d_2=15 mm= 15e-3 m\] Calculating Capacitance: \[C_1=1.1805e-010\] \[C_2=1.1805e-011\] Case 1: when external supply voltage is cut off before movement voltage is give as \[V_1=500\] Finding charge \[Q=C_1V_1=5.9027e-008\] after movement charge is constant. So voltage changes to \[V_2=\frac{Q}{C_2}=5000\] Finding energy \[E_1=\frac{1}{2}C_1V_1^2=1.4757e-005 \approx 14.8\mu J\] \[E_2=\frac{1}{2}C_1V_1^2=1.4757e-004 \approx 148 \mu J\] Case 2: when external supply voltage is maintained at 500V Voltage is constant V_1=V_2=V=500v Finding energy: \[E_1=\frac{1}{2}C_1V^2=1.4757e-005 \approx 14.8\mu J\] \[E_2=\frac{1}{2}C_1V^2=1.4757e-006 \approx 1.48\mu J\]
sgadi
  • sgadi
Gina .... I did a mistake .... in the formula of E2 .... the capacitance is not C1 ... it is C2
Gina
  • Gina
wow!! thank you very much))
sgadi
  • sgadi
welcome
Gina
  • Gina
ok i will check on it
Gina
  • Gina
mr.sgadi do have the notes on this topic?
sgadi
  • sgadi
I don't have any special notes regarding this topic. I used Wikipedea. http://en.wikipedia.org/wiki/Capacitance
Gina
  • Gina
thanx again)
sgadi
  • sgadi
:-) welcome
Gina
  • Gina
what this about this question of maths,,,,∫oadx
sgadi
  • sgadi
I didn't understand. Can you elaborate?
Gina
  • Gina
\[\int\limits_{0}^{a?}d _{x}\]
Gina
  • Gina
can help mathamatics?
sgadi
  • sgadi
yes... to an extent. place in new thread so that everyone will be able to help you.
Gina
  • Gina
can help mathamatics?
sgadi
  • sgadi
yes. please give the question
Gina
  • Gina
\[d _{x}\div \sqrt{x ^{2}+x+1}\]
sgadi
  • sgadi
\[\int{\frac{1}{\sqrt{x^2+x+1}}dx}=\ln{(x+\sqrt{x^2+x+1}+0.5)}\]
Gina
  • Gina
yes that is the question
Gina
  • Gina
is that the solution?
sgadi
  • sgadi
yes ... I have given the solution also

Looking for something else?

Not the answer you are looking for? Search for more explanations.