anonymous
  • anonymous
Inverse of a Function help? Determine whether f(x) and g(x) are inverses of each other. a) f(x) = (√x+1) - 1 b) g(x) = (x + 1)^2 - 1
Mathematics
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anonymous
  • anonymous
Inverse of a Function help? Determine whether f(x) and g(x) are inverses of each other. a) f(x) = (√x+1) - 1 b) g(x) = (x + 1)^2 - 1
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
hard to answer since i cant add pics of graphs but no they arent inverse of eachother
anonymous
  • anonymous
f and g are inverses if operating on one with the other yields x. That is, if f and g are inverses of each other, then\[f(g(x))=x\] and \[g(f(x))=x\]Without restriction, they're not inverses of each other. If they were inverses, they would be mirror images of each other about the line y=x...they're not.
amistre64
  • amistre64
Inverses are known as "one-to-one" functions. g(x)=x^2 is not a one-to-one function. For example: x^2=9, x=3 AND x=-3. In order for g(x) to have in inverse, we have to restrict its domain to either only positive values of x, or only negative values of x.

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