e^y + y cos(x) + (xe^y + sin(x) ) y' = 0 i need two methods to solve this. So far I know it is first order and nonlinear. It does not appear to be separable nor can i use an integrating factor because of e^y. I don't think it is homogeneous, again because of e^y.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

e^y + y cos(x) + (xe^y + sin(x) ) y' = 0 i need two methods to solve this. So far I know it is first order and nonlinear. It does not appear to be separable nor can i use an integrating factor because of e^y. I don't think it is homogeneous, again because of e^y.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

it looks like i can make this a bernoulli type equation but how can i transform e^y to the form of y^n?
Just from looking at it, I think it is an exact differential equation.
ok i will give exact DE method a try. but since i need two methods and it looks like a bernoulli, what can i do about the e^y to make it like q(x)y^n?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

you can't it's not bernoullis
alright, thanks so much for your help.

Not the answer you are looking for?

Search for more explanations.

Ask your own question