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anonymous
 5 years ago
find dy/dx if Y=u^1/3 and u=x^44x^34.
I get 1/3(4x^728x^6+48x^516x^3+48x^2)
This does not seem like it is correct to me.... What do you think?
anonymous
 5 years ago
find dy/dx if Y=u^1/3 and u=x^44x^34. I get 1/3(4x^728x^6+48x^516x^3+48x^2) This does not seem like it is correct to me.... What do you think?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0muraad come to my question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no...answer is \[\left(4x ^{3}12x ^{2} \right)/\left( 3\left( x ^{4}4x ^{3}4 \right)^{1/2} \right)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got to the point of 1/3(x^44x^34)^2/3 (4x^312x^2) for your answer I understand the (4x^312x^2) but for the bottom what happened to the ^2/3? in 1/3(x^44x^34)^ 2/3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0u^(2/3) means 1/[u^(2/3)]. x^2 means 1/(x^2).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh...sorry...I made a mistake...i thought the exponent was 1/2...ill recalculate...gimme a sec

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok...the answer is the same...just the exponent in the denominator turns to 2/3..not 1/2
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