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anonymous
 5 years ago
10 years from now A will be twice as old as B. Five years ago, A was three times as old as B. What are the present ages of A & B?
anonymous
 5 years ago
10 years from now A will be twice as old as B. Five years ago, A was three times as old as B. What are the present ages of A & B?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Set up a system of linear equations: \[A + 10 = 2B\] \[A 5 = 3B\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0One easy way to do that would be to multiply the top equation by 3, then multiply the bottom equation by 2 so that the left sides of both equations are equal to 6B. Then you can set them equal to each other and solve for either A or B to get one of the ages. Then take that value and substitute it back into either equation for solve for the other person's age.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A + 10 = 2 X (B+10) A  5 = 3 X (B5) A = 50 B = 20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ooh, good catch! I spaced the adjusting B's age too.
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