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  • 5 years ago

The equation of the image is . y=-2 (square root 3x -12) -5 What is the base (original) function? Describe the series of transformations. Write the image in the function notation, y = af[k(x - p)] + q.

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  1. anonymous
    • 5 years ago
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    I assume that the base function is the parent function. This is y = f(x) = sqrt(x). I'll revise the equation slightly: \[y=-2\sqrt{3x-12}-5=-2\sqrt{3(x-4)}-5\] The image in function notation is: \[y=-2f(3(x-4))-5\] The transformations undergone here include a vertical stretch by a factor of 2. Also, the image flips reflects over the x-axis (turns upside down). The horizontal stretch is 1/3 (since this "stretch" is less than 1, the image is actually compressed). The image is shifted to the right 4 places and down 5 places.

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