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anonymous
 5 years ago
The equation of the image is .
y=2 (square root 3x 12) 5
What is the base (original) function?
Describe the series of transformations.
Write the image in the function notation, y = af[k(x  p)] + q.
anonymous
 5 years ago
The equation of the image is . y=2 (square root 3x 12) 5 What is the base (original) function? Describe the series of transformations. Write the image in the function notation, y = af[k(x  p)] + q.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I assume that the base function is the parent function. This is y = f(x) = sqrt(x). I'll revise the equation slightly: \[y=2\sqrt{3x12}5=2\sqrt{3(x4)}5\] The image in function notation is: \[y=2f(3(x4))5\] The transformations undergone here include a vertical stretch by a factor of 2. Also, the image flips reflects over the xaxis (turns upside down). The horizontal stretch is 1/3 (since this "stretch" is less than 1, the image is actually compressed). The image is shifted to the right 4 places and down 5 places.
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