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anonymous
 5 years ago
how do you get (n+1) from (n+1)!/(n)! ?
anonymous
 5 years ago
how do you get (n+1) from (n+1)!/(n)! ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think it unravels like this [(n+1)(n)]/[n}, so it gives (n+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because you n's cancel out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(n+1)!/n!= (n+1)(n)(n1)(n2)......./n(n1)(n2)......\] sine the numerator and denominator both have (n)(n1)(n2)..../(n)(n1)(n2)..... they cancel out leaving n+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, it makes a lot of sense. thank you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that was rather simple. thanks guys
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