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anonymous
 5 years ago
Use the Chain Rule to find dw/dt. (Enter your answer only in terms of t.)
w = xey /z, x = t6, y = 9  t, z = 4 + 4t
anonymous
 5 years ago
Use the Chain Rule to find dw/dt. (Enter your answer only in terms of t.) w = xey /z, x = t6, y = 9  t, z = 4 + 4t

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you mean find dw/dt where\[w=\frac{xe^y}{z}, x=t^6, y=9t, z=4+4t?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got an answer I keep on getting the same one, but my hw is online and it marks it wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK. If you really *must* use the chain rule to solve,\[\frac{dw}{dt}=\frac{dw}{dx}\frac{dx}{dy}\frac{dy}{dz}\frac{dz}{dt}\]Then expand dx/dy and dy/dz again\[\frac{dw}{dt}=\frac{dw}{dx}(\frac{dx}{dt}\frac{dt}{dy})(\frac{dy}{dt}\frac{dt}{dz})\frac{dz}{dt}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is for calc 3 so I have to multiply the leibniz notation and add them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ah, okay, knowing the level helps.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, in that case, it's just\[\frac{dw}{dt}=\frac{dw}{dx}\frac{dx}{dt}+\frac{dw}{dy}\frac{dy}{dt}+\frac{dw}{dz}\frac{dz}{dt}\] where all the 'd's are partial.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes I have computed that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm doing the rest...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey lokisan do you get the divisible sign to be straight instead of this /

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I get \[\frac{dw}{dt}=\frac{4t^6}{(4+4t)^2}e^{9t}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Did you need just a check on your answer, or the fullon working?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nadeem, you type "frac{}{}" into the equation editor. Your numerator and denominator go in the first and second parentheses respectively.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's wassup..... appreciate it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that what you get? how did you get that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just doing what each derivative asks of me first\[\frac{dw}{dt}=(\frac{e^y}{z}).t^6+\frac{xe^y}{z}.(1)+(\frac{xe^y}{z^2}).4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then substitute each of the x=t^6, y=... into the above. You should find that the first two quotients cancel out, and you're left with the last quotient > the answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is what I got: \[\frac{dw}{dt}=\frac{4t^5e^{9t}(t^24t6)}{(4+4t)^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{dw}{dt}=(\frac{e^{9t}}{4+4t}).t^6\frac{t^6e^{9t}}{4+4t}4\frac{t^6e^{9t}}{(4+4t)^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The first two parts cancel, the third is left over.
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