how do i solve 4-(-6)/-3

- anonymous

how do i solve 4-(-6)/-3

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- anonymous

can you tell me how you got that?

- anonymous

the two negatives become positives so it becomes 10
so 10/3 = 3 1/3

- anonymous

my answer key says that the answer is -2

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## More answers

- anonymous

Oh, I know what's happening. Use PEMDAS. The division has to happen first, so it's (-6)/(-3), which equals 2. 4-2 is 2.

- anonymous

sorr maybe i should repost this... but the the problem is actually 4-(-6)/-5

- anonymous

It'd be the same thing. Divide -6 by -5, and then subtract that answer from 4.

- anonymous

-6/-5 = 1 1/5
so 4 - 1 1/5 = 2 4/5 = 2.8

- anonymous

-6/-5 = 1 1/5? im sorry but can you explain how you go that answer this is new to me...

- anonymous

when you divide two negatives you get a positive so it would actually be 6/5
then 5 goes into 6 once with 1/5 left over
which gives you 1 1/5

- anonymous

ohhh right improper fractions!!!

- anonymous

yup lol

- anonymous

what about 4- 1 1/5 how do you subtract those?

- anonymous

If you change it to improper fractions it's easier, so instead of 4 it would be 20/5, and instead of 1&1/5 it would be 6/5. Then just subtract 20-6

- anonymous

^ what she said lol

- anonymous

the 20-6 = 14
14/5 = 2 4/5

- anonymous

got it!

- anonymous

only thing is that this asnwer key is saying that the answer is -2????

- anonymous

then they aren't doing PEMDAS.
so then 4- (-6) would equal 10 because the negatives become positive making it 4 + 6
10/ -5 would be -2 because the one negative makes the whole fraction negative

- anonymous

omg so much easier!!!! Thanks nicole you are my new fan!!! :)

- anonymous

i dont even know what PEMDAS is!!!

- anonymous

Sarah i also appreciate your response!!! :)

- anonymous

you'll learn pemdas in the future, but no problemo!

- anonymous

I have another question...

- anonymous

how would you get the square root of something w/out using a calculator????

- anonymous

what's the problem?

- anonymous

actually how do you even get a square root of something?

- anonymous

example.... \[\sqrt{2} X \sqrt{15}=\]

- anonymous

a square root is a number that when multiplied by itself equals a given number
so like the square root of 9 would be 3 because 3*3 = 9
and the square root of 16 would be 4 because 4*4 = 16

- anonymous

but 2 an\[\sqrt{30}\]d 5 dont have square roots.. could the anser to the above be

- anonymous

woa! I messed that up...what i meant was that if 2 and 5 dont have square roots could the anser be
\[\sqrt{30}\]

- anonymous

**15 not 5

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