anonymous
  • anonymous
how do i solve 4-(-6)/-3
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
can you tell me how you got that?
anonymous
  • anonymous
the two negatives become positives so it becomes 10 so 10/3 = 3 1/3
anonymous
  • anonymous
my answer key says that the answer is -2

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anonymous
  • anonymous
Oh, I know what's happening. Use PEMDAS. The division has to happen first, so it's (-6)/(-3), which equals 2. 4-2 is 2.
anonymous
  • anonymous
sorr maybe i should repost this... but the the problem is actually 4-(-6)/-5
anonymous
  • anonymous
It'd be the same thing. Divide -6 by -5, and then subtract that answer from 4.
anonymous
  • anonymous
-6/-5 = 1 1/5 so 4 - 1 1/5 = 2 4/5 = 2.8
anonymous
  • anonymous
-6/-5 = 1 1/5? im sorry but can you explain how you go that answer this is new to me...
anonymous
  • anonymous
when you divide two negatives you get a positive so it would actually be 6/5 then 5 goes into 6 once with 1/5 left over which gives you 1 1/5
anonymous
  • anonymous
ohhh right improper fractions!!!
anonymous
  • anonymous
yup lol
anonymous
  • anonymous
what about 4- 1 1/5 how do you subtract those?
anonymous
  • anonymous
If you change it to improper fractions it's easier, so instead of 4 it would be 20/5, and instead of 1&1/5 it would be 6/5. Then just subtract 20-6
anonymous
  • anonymous
^ what she said lol
anonymous
  • anonymous
the 20-6 = 14 14/5 = 2 4/5
anonymous
  • anonymous
got it!
anonymous
  • anonymous
only thing is that this asnwer key is saying that the answer is -2????
anonymous
  • anonymous
then they aren't doing PEMDAS. so then 4- (-6) would equal 10 because the negatives become positive making it 4 + 6 10/ -5 would be -2 because the one negative makes the whole fraction negative
anonymous
  • anonymous
omg so much easier!!!! Thanks nicole you are my new fan!!! :)
anonymous
  • anonymous
i dont even know what PEMDAS is!!!
anonymous
  • anonymous
Sarah i also appreciate your response!!! :)
anonymous
  • anonymous
you'll learn pemdas in the future, but no problemo!
anonymous
  • anonymous
I have another question...
anonymous
  • anonymous
how would you get the square root of something w/out using a calculator????
anonymous
  • anonymous
what's the problem?
anonymous
  • anonymous
actually how do you even get a square root of something?
anonymous
  • anonymous
example.... \[\sqrt{2} X \sqrt{15}=\]
anonymous
  • anonymous
a square root is a number that when multiplied by itself equals a given number so like the square root of 9 would be 3 because 3*3 = 9 and the square root of 16 would be 4 because 4*4 = 16
anonymous
  • anonymous
but 2 an\[\sqrt{30}\]d 5 dont have square roots.. could the anser to the above be
anonymous
  • anonymous
woa! I messed that up...what i meant was that if 2 and 5 dont have square roots could the anser be \[\sqrt{30}\]
anonymous
  • anonymous
**15 not 5

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