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anonymous

  • 5 years ago

how do i solve 4-(-6)/-3

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  1. anonymous
    • 5 years ago
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    can you tell me how you got that?

  2. anonymous
    • 5 years ago
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    the two negatives become positives so it becomes 10 so 10/3 = 3 1/3

  3. anonymous
    • 5 years ago
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    my answer key says that the answer is -2

  4. anonymous
    • 5 years ago
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    Oh, I know what's happening. Use PEMDAS. The division has to happen first, so it's (-6)/(-3), which equals 2. 4-2 is 2.

  5. anonymous
    • 5 years ago
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    sorr maybe i should repost this... but the the problem is actually 4-(-6)/-5

  6. anonymous
    • 5 years ago
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    It'd be the same thing. Divide -6 by -5, and then subtract that answer from 4.

  7. anonymous
    • 5 years ago
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    -6/-5 = 1 1/5 so 4 - 1 1/5 = 2 4/5 = 2.8

  8. anonymous
    • 5 years ago
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    -6/-5 = 1 1/5? im sorry but can you explain how you go that answer this is new to me...

  9. anonymous
    • 5 years ago
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    when you divide two negatives you get a positive so it would actually be 6/5 then 5 goes into 6 once with 1/5 left over which gives you 1 1/5

  10. anonymous
    • 5 years ago
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    ohhh right improper fractions!!!

  11. anonymous
    • 5 years ago
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    yup lol

  12. anonymous
    • 5 years ago
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    what about 4- 1 1/5 how do you subtract those?

  13. anonymous
    • 5 years ago
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    If you change it to improper fractions it's easier, so instead of 4 it would be 20/5, and instead of 1&1/5 it would be 6/5. Then just subtract 20-6

  14. anonymous
    • 5 years ago
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    ^ what she said lol

  15. anonymous
    • 5 years ago
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    the 20-6 = 14 14/5 = 2 4/5

  16. anonymous
    • 5 years ago
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    got it!

  17. anonymous
    • 5 years ago
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    only thing is that this asnwer key is saying that the answer is -2????

  18. anonymous
    • 5 years ago
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    then they aren't doing PEMDAS. so then 4- (-6) would equal 10 because the negatives become positive making it 4 + 6 10/ -5 would be -2 because the one negative makes the whole fraction negative

  19. anonymous
    • 5 years ago
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    omg so much easier!!!! Thanks nicole you are my new fan!!! :)

  20. anonymous
    • 5 years ago
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    i dont even know what PEMDAS is!!!

  21. anonymous
    • 5 years ago
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    Sarah i also appreciate your response!!! :)

  22. anonymous
    • 5 years ago
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    you'll learn pemdas in the future, but no problemo!

  23. anonymous
    • 5 years ago
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    I have another question...

  24. anonymous
    • 5 years ago
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    how would you get the square root of something w/out using a calculator????

  25. anonymous
    • 5 years ago
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    what's the problem?

  26. anonymous
    • 5 years ago
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    actually how do you even get a square root of something?

  27. anonymous
    • 5 years ago
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    example.... \[\sqrt{2} X \sqrt{15}=\]

  28. anonymous
    • 5 years ago
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    a square root is a number that when multiplied by itself equals a given number so like the square root of 9 would be 3 because 3*3 = 9 and the square root of 16 would be 4 because 4*4 = 16

  29. anonymous
    • 5 years ago
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    but 2 an\[\sqrt{30}\]d 5 dont have square roots.. could the anser to the above be

  30. anonymous
    • 5 years ago
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    woa! I messed that up...what i meant was that if 2 and 5 dont have square roots could the anser be \[\sqrt{30}\]

  31. anonymous
    • 5 years ago
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    **15 not 5

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