anonymous
  • anonymous
if the length of a rectangle is x+1/x and the width is x+2/2 what is the perimeter of the rectangle?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
if the length of a rectangle is (x+1/x) and the width is (x+2/2) what is the perimeter of the rectangle?
helpmeplease
  • helpmeplease
Perimeter of a rectangle = 2l+2w. Just multiply both expressions by two, and add them. That is the perimeter.
anonymous
  • anonymous
thats what i tried doing but i think im doing it wrong cuz i get a weird answer

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helpmeplease
  • helpmeplease
What do you mean by weird answer? The result should be a function of x.
anonymous
  • anonymous
i get x=2 and x=-1
anonymous
  • anonymous
but a measurement cant be negative right?
helpmeplease
  • helpmeplease
Well, when you multiply the expressions, you should get Perimeter = 2(x+1/x)+2(x+2/2)
helpmeplease
  • helpmeplease
Also, 2/2 = 1, so simplify. I'm not sure whether you mean (x+2)/2 or x+2/2
anonymous
  • anonymous
its just x+2/2
helpmeplease
  • helpmeplease
That means you have to distribute the 2 into both functions, and add the result.

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