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anonymous

  • 5 years ago

Show that if a collection of vectors are linearly dependent, that any collection of it's vectors must also be linearly dependent

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  1. helpmeplease
    • 5 years ago
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    Multiply each vector with C's and then set the linear combination of them equal to zero. Solve for each component. If you eventually find that the C's are nonzero, you can conclude that the vectors are dependent. If they equal zero, they are linearly independent. Depending on whether the vectors are solutions to a differential equation, you can also use the Wronskian.

  2. helpmeplease
    • 5 years ago
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    Triple post, my bad.

  3. anonymous
    • 5 years ago
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    the vector set they give us is [B1, B2,....Bm],

  4. helpmeplease
    • 5 years ago
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    Do \[C_1B_1+C_2B_2+C_NB_N=0\] and factor where possible.

  5. anonymous
    • 5 years ago
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    k thanks, do you see where this would be proven though?

  6. anonymous
    • 5 years ago
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    nvm I think I read the question wrong

  7. helpmeplease
    • 5 years ago
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    Are you figuring out subspaces?

  8. anonymous
    • 5 years ago
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    the question is if the vectors B1,B2..Bn is linearly dependent, then any collection of vectors which contains these vectors is also linearly independent....which is easy

  9. anonymous
    • 5 years ago
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    Show that two planar vectors alpha and beta are linearly independent if and only if they are not parallel

  10. helpmeplease
    • 5 years ago
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    The idea is, the vectors are parallel, then they can be scalar multiples of eachother. That implies that \[C_1\] and \[C_2\] are constants, therefore they are dependent.

  11. anonymous
    • 5 years ago
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    Show that three vectors a,b,y which lie in the same plane must be linearly dependent

  12. helpmeplease
    • 5 years ago
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    Same idea as the last part. If vectors are colinear in the plane, then they must be dependent. If not, a linear combination of any two vectors can be colinear with the other, meaning that they are linearly dependent. Same logic, more gimmicks.

  13. anonymous
    • 5 years ago
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    So if they are all in the same plane, they can be represented by some variation of (S1V1+S2V2=a)

  14. helpmeplease
    • 5 years ago
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    Yep.

  15. anonymous
    • 5 years ago
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    k thanks again, how you feeling about your test tomorrow/

  16. helpmeplease
    • 5 years ago
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    Pretty good. I'm not too worried, just gotta be able to derive something if I go absent minded.

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