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anonymous

  • 5 years ago

sorry... i know this is a lame question but... to write an expression as a positive exponent should i just change the negative exponent to a positive one? for example.. 7^-2 would just be 7^2 right?

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  1. anonymous
    • 5 years ago
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    You would move it to the denominator to make the exponent positive: \[a^{-n}=\frac{1}{a^n}\rightarrow 7^{-2}=\frac{1}{7^2}\]

  2. anonymous
    • 5 years ago
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    Oh okay so basically you just put it under 1 with the positive exponent?

  3. anonymous
    • 5 years ago
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    You would move it to the denominator to make the exponent positive: \[a^{-n}=\frac{1}{a^n}\rightarrow 7^{-2}=\frac{1}{7^2}\]

  4. anonymous
    • 5 years ago
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    yeah but sometime you end up with a reversed scenario such as: \[\frac{1}{5^{-3}}\] in this case you would move it to the numerator to make it positive \[\frac{1}{5^{-3}}\rightarrow 5^3\]

  5. anonymous
    • 5 years ago
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    ah cool thanks :D but i have another question XD... what if for example you have... ab^-2c or something like x^-2y^-3? i have similar problems further along but figured id ask now x]

  6. anonymous
    • 5 years ago
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    Is the first one \[(ab)^{-2c}, or, ab^{-2c}\]

  7. anonymous
    • 5 years ago
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    its \[ab ^{-2}c\] and \[x ^{-2}y ^{-3}\]sorry forgot about the equation button

  8. anonymous
    • 5 years ago
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    in the case of \[ab^{-2c}\] only b is raised to the negative exponent of -2c, so you would move b to the denominator\[ab^{-2c}=\frac{a}{b^{2c}}\] in the case of \[x^{-2}y^{-3}\] both x and y are raised to a negative exponent, so you would move both of them to the denominator\[x^{-2}y^{-3}=\frac{1}{x^2y^3}\]

  9. anonymous
    • 5 years ago
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    well the c isnt part of the b^-2 exponent its like b^-2 and c alone

  10. anonymous
    • 5 years ago
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    oh, sorry.... well then b will move to the denominator bc it carries a negative exponent\[ab^{-2}c=\frac{ac}{b^2}\]

  11. anonymous
    • 5 years ago
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    oh ok i get it now thanks for your help =]

  12. anonymous
    • 5 years ago
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    no problem

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