## anonymous 5 years ago I'm wondering. If y(x)=K for all integer x. Is y(x) also considered as bounded?

1. anonymous

K is a constant.

2. anonymous

y(x) is bounded if$y(x)\le M$for all x in your domain and where M some constant. You have this condition:$y(x)=K \rightarrow y(x)\le K$ (you can choose your constant M to be K).

3. anonymous

That is, y(x) is bounded for all x an integer.

4. anonymous

thanks..

5. anonymous

No probs.