y''=8*y*3 I am supposed to solve this equation by multiplying both sides of the equation with y' , but I don't know what to do thereafter The answer shall be: y=1/(C+-2x) But I don't know how to get it, can anybody tell me the steps?

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y''=8*y*3 I am supposed to solve this equation by multiplying both sides of the equation with y' , but I don't know what to do thereafter The answer shall be: y=1/(C+-2x) But I don't know how to get it, can anybody tell me the steps?

Mathematics
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I just don't quite see what to do just after having multiplied with y' , can you give me some hints?
what isthe question, is it 8y^3?
The question is the differential equation y''=8y^3

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Other answers:

You can solve using laplace transforms
or actually nevermind you aren't given initial conditions
ok, you just substitute v=y' then using chain rule y''=v*dv/dy. Sub everythign back into original and you get a separable equation with y's and v's
ok, thank you very much

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