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anonymous

  • 5 years ago

Find all points on the graph of the function f(x)=x^2/x+2 where the tangent line is horizonal. I get to x^2+4x/(x+2)^2 Then I get to x=-4 and x=0. Am I on the right path?

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  1. anonymous
    • 5 years ago
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    tangent line horizontal is a slope of 0, so when you have the derivative (which you have is correct) equalling 0, this is the answer. yes, you are correct.

  2. anonymous
    • 5 years ago
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    Yes. The roots of x(x+4)=0 are 0 and -4 respectively

  3. anonymous
    • 5 years ago
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    so i get one point as (-4,-8) when I replace the 0 i get 0/2, so will this not be a point where the tangent line is horizonal?

  4. anonymous
    • 5 years ago
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    Plug the solutions into f(x) one at a time to obtain the associated y coordinate. The coordinates of the points of interest are (0,0) and (-4,-8 ).

  5. anonymous
    • 5 years ago
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    http://www.coolmath.com/graphit/ provides an online graphing program. Plot x^2/(x+2). The curve in the area of the origin, (0,0) is hardly curving, however, the tangent line at the point (0,0) seems to the casual observer to be parallel to the x axis, ie: horizontal. The other tangent line at (-4,-8) easier to verify.

  6. anonymous
    • 5 years ago
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    Thanks

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