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anonymous
 5 years ago
tan(45+a)tan(45a)
anonymous
 5 years ago
tan(45+a)tan(45a)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[={(1+tana)/1tana}{(1tana)/1+tana}\]\[{(1+tana)^2(1tana)^2}/1\tan^2a\]\[=4tana/1\tan^2a\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Scroll down to "The Other Identities" section at the following web site: http://library.thinkquest.org/20991/alg2/trigi.html There you will find these identities for Tan(A+B) and Tan(AB): tan (A + B) = (tan A + tan B)/(1  (tan A)(tan B)) tan (A  B) = (tan A  tan B)/(1 + (tan A)(tan B)) From the problem it is assumed that tan(45) is the tangent of 45 degrees, which is 1. Thus tan(45+a)tan(45a) > \[(1+\tan a)/(1\tan a)(1\tan a/(1+\tan a)\] When he above expression is combined and simplified, the result is: \[2 \tan 2a\] Note: If any one can show that final result is invalid, I'm certain that Wolfram Research would be glad to hear from you.
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